In which of the following reactions is the product not an alkane?

  • A
    $CH_3-CH_2-I \xrightarrow{Na/Ether, \Delta}$
  • B
    $CH_3-COONa \xrightarrow{Electrolysis}$
  • C
    $CH_3-COOH \xrightarrow{NaOH + CaO, \Delta}$
  • D
    $CH_3-COOAg \xrightarrow{Br_2/CCl_4, \Delta}$

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Consider the following:
Statement-$I$ : Kolbe's electrolysis of sodium propionate gives $n$-hexane as product.
Statement-$II$ : In Kolbe's process,$CO_2$ is liberated at the anode and $H_2$ is liberated at the cathode.
The correct answer is:

Which of the following $C-H$ bonds has the lowest bond dissociation energy?

$A$ gaseous alkane undergoes complete combustion with oxygen. The ratio of the volume of $O_2$ required to the volume of $CO_2$ formed is $7 : 4$. The molecular formula of the alkane is:

When a certain alkane is mixed with chlorine and irradiated with ultraviolet light,only one monochloroalkane is formed. This alkane is likely to be:

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How many carbon atoms does an alkane (not a cycloalkane) need before it is capable of existing in an enantiomeric form?

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